Multiplication Table – Simple Vedic Mathematics Technique helps to remember it easily
To remember the multiplication table, consider the sum of the multiplicand and the multiplier.
Remember the values of the addition 10 (all other values of the multiplication table) using the simple technique of Vedic mathematics.
The method we follow, here, is very simple to understand and very easy to follow.
The method is based on the “Nikhilam” sutra of Vedic mathematics.
The method will become clear from the following examples.
Example 1:
Suppose we have to find 9 x 6.
First we write one below the other.
9
6
Then we subtract the digits from 10 and write the values (10-9=1; 10-6=4) to the right of the digits with a ‘-‘ sign in between.
9 – 1
6 – 4
The product has two parts. the first part is the cross difference (here it is 9 – 4 = 6 – 1 = 5).
the second part is the vertical product of the digits on the right (here it is 1 x 4 = 4).
We write the two parts separated by a slash.
9 – 1
6 – 4
—–
5/4
—–
So, 9 x 6 = 54.
Let’s look at one more example.
Example 2:
Suppose we have to find 8 x 7.
First we write one below the other.
8
7
Then we subtract the digits from 10 and write the values (10-8=2; 10-7=3) to the right of the digits with a ‘-‘ sign in between.
8 – 2
7 – 3
The product has two parts. the first part is the cross difference (here it is 8 – 3 = 7 – 2 = 5).
the second part is the vertical product of the digits on the right (here it is 2 x 3 = 6).
We write the two parts separated by a slash.
8 – 2
7 – 3
—–
5/6
—–
So 8 x 7 = 56.
Let’s look at one more example.
Example 3:
Suppose we have to find 9 x 9.
First we write one below the other.
9
9
Then we subtract the digits from 10 and write the values (10-9=1; 10-9=1) to the right of the digits with a ‘-‘ sign in between.
9 – 1
7 – 1
The product has two parts. the first part is the cross difference (here it is 9 – 1 = 9 – 1 = 8).
the second part is the vertical product of the digits on the right (here it is 1 x 1 = 1).
We write the two parts separated by a slash.
9 – 1
9 – 1
—–
8/1
—–
So 9 x 9 = 81.
In the following examples, the second part has two digits.
Let’s see how to handle the problem.
Example 4:
To find 7 x 6
First we write one below the other.
7
6
Then we subtract the digits from 10 and write the values (10-7=3; 10-6=4) to the right of the digits with a ‘-‘ sign in between.
7 – 3
6 – 4
The product has two parts. the first part is the cross difference (here it is 7 – 4 = 6 – 3 = 3).
the second part is the vertical product of the digits on the right (here it is 3 x 4 = 12).
We write the two parts separated by a slash.
7 – 3
6 – 4
—–
3/12
—–
The second part, here, has two digits.
us keep the units digit (2 and transfer the other digit (1) to the left.
7 – 3
6 – 4
————–
(3+1)/2 = 4/2
————-
So the answer becomes (3+1)/2 = 4/2
Therefore, 7 x 6 = 42.
Example 5:
To find 8 x 3
Following the above procedure, we can write the following.
8 – 2
3 – 7
—–
2/14
—–
The first part = 8 – 7 = 3 – 2 = 1.
The second part here is 2×7 = 14.
It has two digits. us keep the units digit (4) and transfer the other digit (1) to the left.
8 – 2
3 – 7
————–
(1+1)/4 = 2/4
————-
So the answer becomes (1+1)/4 = 2/4
Therefore, 8 x 3 = 24.
Let’s look at one last example.
Example 6:
To find 6 x 5
Following the above procedure, we can write the following.
6 – 4
5 – 5
—–
1/20
—–
The first part = 6 – 5 = 5 – 4 = 1.
The second part here is 4 x 5 = 20.
It has two digits. us keep the units digit (0) and transfer the other digit (2) to the left.
6 – 4
5 – 5
————–
(1+2)/0 = 3/0
————-
So the answer becomes (1+2)/0 = 3/0
Therefore, 6 x 5 = 30.
Therefore, we can arrive at any value up to 10 x 10.